Question 410355
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Hi
graph (y=1/5x-2).
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
  y = (1/5)x - 2  |y-intercept is Pt(0,-2)
Note: as y increases/decreases by 1, x increases/decreases by 5   
Pt(5, -1) and Pt(-5, -3) on the Line.  Plotting Pts and connecting with line
{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(0, -2,0.3),
circle(5, -1,0.3),
circle(-5, -3,0.3),
graph( 300, 300, -6, 6, -6, 6,0, .2x -2))}}}