Question 406344
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Hi
Find three consecutive integers 
Let x, (x+1), (x+2) represent the three consecutive integers respectively
Question states***
  8[x+ (x+1)+ (x+2)] = 21x + 108
Solving for x
    8(3x + 3) = 21x + 108
      24x + 24 = 21x + 108
           3x = 84
             x = 28  The three consecutive integers are 28,29,30
          
CHECKING our Answer***
   8*87 = 696 = 588 + 108