<PRE><B>Question 410182</B>
nurseryman is preparing an insecticide by mixing a 95% solution with water (0% solution).
 How much solution and how much water are needed to fill a 500 gal tank with 3.8% solution?
:
Let x = amt of water required
let (500-x) = amt of insecticide required
:
A simple equation
.95(500-x) = .038(500)
475 - .95x = 19
475 - 19 = .95x
456 = .95x
x = {{{456/.95}}}
x = 480 gal of water,
 then
20 gal of insecticide
:
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