<PRE><B>Question 410111</B>
Find the maximum or minimum value of the function 
defined by f(x)= -x^2-6x-8.
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Since x^2 has a negative coefficient,
the parabola opens down.
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Max occurs when x = -b/2a = 6/(-2) = -3
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Max value is f(-3) = -(-3)^2-6(-3)-8 = -9+18-8 = 1
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{{{graph(400,300,-10,10,-15,5,-x^2-6x-8)}}}
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Cheers,
Stan H.
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