Question 409974
{{{log(((x^2+6x+9)/(x^2-9)))}}}
First let's simplify the argument. We can reduce this fraction if we factor it:
{{{log((((x+3)(x+3))/(x+3)(x-3)))}}}
Now we can cancel the common factor:
{{{log(((cross((x+3))(x+3))/cross((x+3))(x-3)))}}}
{{{log(((x+3)/(x-3)))}}}
Now let's expand it. To expand it we will use a property of logarithms, {{{log(a, (p/q)) = log(a, (p)) - log(a, (q))}}}, which allows us to split the log of a quotient into the difference of the logs of the numerator and denominator:
{{{log((x+3)) - log((x-3))}}}