Question 409783
 <pre><font size = 3 color = "indigo"><b>
Hi
line that passes through (-4, 0) and is parallel to y= -2x+1
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
y= -2x+1   |slope m = -2.  Parallel lines have identical slopes  
New Line: m = -1/3   |Note: 3*-1/3 = -1
 y = -2x + b   |using ordered pair Pt(-4,0) to solve for b
 0 = 8 + b
 -8 = b 
 y = -2x -8  |written in slope-intercept form
{{{drawing(300,300,   -10,10,-10,10,
 grid(1),
circle(0, 1,0.4),
circle(-4, 0,0.4),
circle(0, -8,0.4),

graph( 300, 300, -10,10,-10,10,0,-2x+1,-2x -8  ))}}}