Question 409709
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Hi
line that passes through (3, -2) and is perpendicular to y=3x-4*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
y=3x-4    |slope m = 3  
perpendicular lines have slopes that are neagtive reciprocals of one another
New Line: m = -1/3   |Note: 3*-1/3 = -1
 y = (-1/3)x + b   |using ordered pair Pt(3,-2) to solve for b
-2 = -1 + b
 -1 = b 
 y = (-1/3)x - 1 |written in slope-intercept form
{{{drawing(300,300,   -10,10,-10,10,
 grid(1),
circle(0, -1,0.4),
circle(3, -2,0.4),
circle(0, -4,0.4),

graph( 300, 300, -10,10,-10,10,0,3x-4,(-1/3)x - 1  ))}}}