Question 409825
 <pre><font size = 3 color = "indigo"><b>
Hi
line that passes through (-2, 3) and is perpendicular to 2x – 9y = -12 
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
2x – 9y = -12 OR y = (2/9)x + 12/9  |slope m = 2/9.  
perpendicular lines have slopes that are neagtive reciprocals of one another
New Line: m = -9/2   |Note: 2/9*-9/2 = -1
 y = (-9/2)x + b   |using ordered pair Pt(-2,3) to solve for b
 3 = 9 + b
 -6 = b 
  y = (-9/2)x -6  |written in slope-intercept form
{{{drawing(300,300,   -10,10,-10,10,
 grid(1),
circle(0, -6,0.4),
circle(-2, 3,0.4),
circle(0, 4/3,0.4),

graph( 300, 300, -10,10,-10,10,0,-4.5x -6,(2/9)x + 12/9  ))}}}