Question 409987
(x-3)^2=-9
(x-3)(x-3)+9=0
x^2-3x-3x+9+9=0
x^2-6x+18=0 
x = [-6+-sqrt((-6)^2-4(1)(18))]/2(1)
x = [-6+-sqrt(36-72)]/(2)
x = [-6+-sqrt(-36)]/(2)
---
I changed your next step because sqrt(-36) is 6i
---
x = [(-6+-(6)i)/(2)
---
2 is a common denominator so you get:
--------------
x = -3+3i or x = -3-3i
============================
Cheers,
Stan H.