Question 409904
I'm guessing that "calculator ready" assumes that your calculator has a button for "e", the base of natural logarithms.<br>
ln(3x+5) = 5
We start be rewriting this in exponential form. In general {{{log(a, (p)) = q}}} is equivalent to {{{p = a^q}}}. Using this pattern on your expression we get:
{{{3x+5 = e^5}}}
Now we solve for x. Subtracting 5 from each side:
{{{3x = e^5 - 5}}}
Dividing by 3 we get:
{{{x = (e^5 - 5)/3}}}