Question 409741
For the parabola x^2 - 8x - y + 19 = 0,
1. Convert the equation to vertex form
x^2-8x+16 = y-19+16
(x-4)^2 = y-3
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2. Find the vertex: (4,3)
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3. Find the axis of symmetry: x = 4
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4. Find the focus
4p = 1
p = 1/4
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Focus: (4,13/4)
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5. Find the directrix
y = 4-(1/4) = 15/4
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{{{graph(400,300,-10,10,-10,10,(x-4)^2+3)}}}
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Cheers,
Stan H.