Question 409640
{{{7/(2x + 1) + 8/(2x - 1) = -4}}}
Multiply both sides by {{{(2x + 1)*(2x - 1)}}}
{{{7*(2x - 1) + 8*(2x + 1) = -4*(4x^2 - 1)}}}
{{{14x - 7 + 16x + 8 = -16x^2 + 4}}}
{{{30x + 1 = -16x^2 + 4}}}
{{{16x^2 + 30x - 3 = 0}}}
Use quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a = 16}}}
{{{b = 30}}}
{{{c = -3}}}
{{{x = (-30 +- sqrt( 30^2-4*16*(-3) ))/(2*16) }}}
{{{x = (-30 +- sqrt( 900 + 192 )) / 32 }}}
{{{x = (-30 +- sqrt( 1092 )) / 32 }}}
{{{1092}}} isn't a perfect square, so maybe I made 
a mistake. I think the method is OK, though