Question 409500


{{{32-8y>-4(y-10)}}} Start with the given inequality.



{{{32-8y>-4y+40}}} Distribute.



{{{-8y>-4y+40-32}}} Subtract {{{32}}} from both sides.



{{{-8y+4y>40-32}}} Add {{{4y}}} to both sides.



{{{-4y>40-32}}} Combine like terms on the left side.



{{{-4y>8}}} Combine like terms on the right side.



{{{y<(8)/(-4)}}} Divide both sides by {{{-4}}} to isolate {{{y}}}. note: Remember, the inequality sign flips when we divide both sides by a negative number. 



{{{y<-2}}} Reduce.



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Answer:


So the answer is {{{y<-2}}} 



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