Question 43927
{{{ y = (8x-12)/(4x-2) }}}
{{{ y(4x-2) = 8x-12 }}}
{{{ 4xy-2y = 8x-12 }}}
{{{ 4xy-2y-8x = -12 }}}
{{{ 4xy-8x = 2y-12 }}}
{{{ x(4y-8) = 2y-12 }}}
{{{ x = (2y-12)/(4y-8) }}}


So, this version says that when 4y-8=0 we have the value of y for the asymptote.


4y = 8
y = 8/4
y = 2


jon