Question 409459
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Hi
Solving
(4x+9)(15x^2-7x-2) =0    |the concept is finding products = 0 to solve for x
factoring further:
factoring the (15x^2-7x-2)portion: factoring: expressing as 2 products..
In this case: (_x    1)(_x   2)|the hint here is the -7x middle term
         (4x+9)(5x + 1)(3x - 2)= 0 |strategically placing the 5 and 3 & ± works
      Note:SUM of the inner product(3x) and the outer product(-10x) = -7x
(4x+9)(5x+1)(3x -2)= 0  |NOW we are prepared to solve for x(s)
(4x+9)= 0    x = -9/4
(5x+1)= 0    x = -1/5
(3x -2)= 0   x = 2/3
Solution set is x = {-9/4,-1/5,2/3}