Question 408921
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Hi
*[tex \LARGE\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
Graph the line with slope -3/4 passing through the point (5,-3)
 y = (-3/4)x + b   |using ordered pair Pt(5,-3) to solve for b
-3 = -15/4 + b
 3/4 = b
 y = (-3/4)x + 3/4  | m = -3/4 and y-intercept is Pt(0, 3/4)
Note: as y increases/decreases by 3, x increases/decreases by 4 in opposite direction
 Thus Pt(4,-2 1/4) and Pt(-4, 3 3/4) are on the Line
{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(0, .75,0.3),
circle(4, -2.25,0.3),
circle(-4, 3.75,0.3),
graph( 300, 300, -6, 6, -6, 6,-.75x + .75))}}}