Question 409389
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Hi
graph using the slope and the y intercept
*[tex \large\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
x+4y=8  OR y = (-1/4)x + 2  |slope m = -1/4 and y-intercept is Pt(0,2)
Note: as y increases/decreases by 1, x increases/decreases by 4 in opposite direction
 Thus, Pt(4,1) and Pt(-4,3) on this Line
{{{drawing(300,300,   -6, 6, -6, 6,  grid(1),
circle(0, 2,0.3),
circle(4, 1,0.3),
circle(-4, 3,0.3),
graph( 300, 300, -6, 6, -6, 6,-.25x+2))}}}