<PRE><B>Question 409158</B>
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Sign Error:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b^2\ -\ 4ac\ =\ 4\ -\ 4(1)(-168)\ =\ 4\ -\ (-672)\ =\ 4\ +\ 672\ =\ 676\ =\ 26^2]


So it is a perfect square after all.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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