Question 43871
Factor completely:
{{{-3t^3+3t^2-6t}}} First look for a factor that is common to each term.  It looks like -3t is a common factor so factor this out.
{{{-3t(t^2-t+2)}}} Now see if the factor inside the parentheses is factorable. 
Assume the factors will be:{{{(t+a)(t+b)}}}
Can you find a & b such that:
a*b = 2 and a + b = -1

The factors of 2 are:
(1)(2) or
(-1)(-2)

Neither of these pairs will add up to -1.

So I would conclude that you cannot factor the expression any further than:

{{{-3t^3+3t^2-6t = -3t(t^2-t+2)}}}