Question 408997
<pre>
            -5x  + (-5)
            _______________________________________    
-5x^2-3x-2 /25x^3+40x^2+25x+10
            25x^2+15x^2+10x
            ---------------
                  25x^2+15x+10
                  25x^2+15x+10
                  ------------
                             0
</pre>
There is a remainder of zero so -5x^2-3x-2 divided evenly into 25x^3+40x^2+25x+10. So:
{{{(25x^3+40x^2+25x+10)/(-5x^2-3x-2) = -5x + (-5)}}} or -5x-5