Question 408741
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Hi
A planes flies south at 192mph. Two hours later another plane leaves at 960mph
Let x and (x-2)represent times traveled respectively
 D = rt (Distance traveled the same for both planes)
  192x = 960(x-2)
   1920 = 768 x
     x = 2.5 hrs , time traveled by slower plane.
Second plane will pass the first plane in 1/2 hr OR 30min.

CHECKING our Answer***
192*2.5 = 480mi = 960*(1/2)