Question 408821
Write exactly what it says
:
Let x = a number
let y = another number
:
a: One number is 3 more than twice another number.
x = 3 + 2y
 find the larger number if their sum is -15
x + y = -15
From the 1st statement, replace x with (3+2y)
(3+2y) + y = -15
2y + y = -15 - 3
3y = -18
y = {{{(-18)/3}}}
y = -6 
find x using the 1st equation
x = 3 + 2(-6)
x = 3 - 12
x = -9
Check solutions in the 2nd equation
-9 - 6 = -15; confirms our solution of x=-9, y=-6 (which is the larger number)
:
:
Five consecutive integers: x, (x+1), (x+2), (x+3), (x+4)
b: The sum of smallest and largest of 5 consecutive integer is -50.
x + (x+4) = -50
2x + 4 = -50
2x = -50 - 4
2x = -54
x = {{{(-54)/2}}}
x = -27 is the 1st integer
:
find the middle integer. That's (x+2), therefore:
-27 + 2 = -25 is the middle integer
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Did this shed some light on this stuff for you?