Question 408847
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Hi
Solving the following expression using a 'common base':
(1/2)^(4x+1)=(1/4)^(3x+3) 
(1/2)^(4x+1)=(1/2)^2(3x+3)
     4x+ 1 = 2(3x+3)
     4x+ 1 = 6x+6
         -5 = 2x
        -5/2 = x 
CHECKING our Answer***
(1/2)^-9 = (1/4)^(-9/2)= (1/2)^-9