Question 43879
Use log(5) 2≈0.4307 and log(5) 3≈0.6826 to approximate the value of log(5) 12.


Log(5)12 = Log(5)[3*2^2] = log(5)3 + 2log(5)2
=0.4307 +2(0.6826)
=1.7959

Cheers,
Stan H.