Question 408765
Dividing both sides by -2, we obtain


{{{abs(3x-4) > -8}}} (don't forget to switch the inequality sign). However, since{{{abs(3x-4) >= 0}}} for all real x, then for all x,


{{{abs(3x-4) >= 0 > -8}}} so all real numbers x satisfy.


When you learn about complex numbers you'll see that all complex solutions satisfy. However {{{abs(3x-4)}}} doesn't denote absolute value anymore, it denotes the magnitude of the number (similar to absolute value, but in two dimensions).