Question 43880
Determine the vertex of y=x^2-8x+22.  Thank you!

Put the equation in vertex form by completing the square, as follows:

y-22=x^2-8x
y-22+16=x^2-8x+4^2
y-6=(x-4)^2

Vertex is at (4,6).
This is what it looks like.
*[invoke quadratic "x",1,-8,22]
Cheers,
Stan H.