Question 408667
Assume that the mixture is thoroughly mixed, and that initially the ratio of red to green to blue dye is 1 :1:1.
Let x = weight of each of the red, green, and blue dye.
==> total weight of mixture is 3x.
After half of the mixture was spilled, there remains 3x/2 of the mixture.
This was also the weight of the green dye that was put into the mixture after the spill.
Also, after the spill, the weight of each dye is x/2.
Then the new weight of the green dye is 3x/2 + x/2 = 2x.
The weight of each of the red and blue dye is still x/2.
Hence the ratio of red to green to blue dye is 1/2: 2: 1/2, or 1:4:1.