Question 408682
The ln function shouldn't be too far beyond your reach, since ln is a logarithm function (except it uses the base {{{e}}}, where e = 2.71828.... e is a very important number in calculus).


The easiest way to solve this is to isolate the 1 on the exponent x+1 to obtain


{{{2^x = 3*3^x}}} Divide both sides by {{{3^x}}}


{{{(2^x)/(3^x) = 3}}}

{{{(2/3)^x = 3}}}

Take the log base 2/3 of both sides to obtain


{{{x = log(2/3, 3)}}} = -2.709511...