Question 408536

The length {{{L}}} of a rectangle is {{{7in}}} greater than its width {{{W}}}.  The perimeter {{{P}}} of the rectangle is {{{50"}}}.   

Find the length {{{L}}} and width {{{W}}} of the rectangle.
 
 {{{P=2(L+W)}}}

{{{50in=2(L+W)}}}


given:{{{L}}} of a rectangle is {{{7"}}} greater than its width {{{W}}}..=>


{{{L=W+7in}}}.....

{{{50in=2(W+7in+W)}}}.divide by 2

{{{25in=2W+7in}}}

{{{25in-7in=2W}}}

{{{18in=2W}}}

{{{18in/2=W}}}

{{{9in=W}}}

{{{L=W+7in}}}.....


{{{L=9in+7in}}}.....

{{{L=16in}}}.....


check:

{{{50in=2(16in+9in)}}}

{{{50in=2(25in)}}}
{{{50in=50in)}}}