Question 408536
The length of a rectangle is 7" greater than its width. The perimeter of the rectangle is 50". Find the length and width of the rectangle.

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Perimeter = 2(length + width)
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Let width be "x".
The length is "x+7".
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50 = 2(x+7 + x)
25 = 2x+7
2x = 18
x = 9 (width)
x+7 = 16 (length)
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Cheers,
Stan H.