Question 408521
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Hi
length of a rectangle is 2 meters more than its width.
Let x and (x+2) represent the width and length respectively
Question states***
x(x+2) = 35 m^2
Solving for x
 x^2 + 2x - 35 = 0
factoring
(x+7)(x-5)= 0 Note:SUM of the inner product(7x) and the outer product(-5x) = 2x
 (x+7)=0  |tossing out negative solution for length
 (x-5)= 0  x = 5m, the width.  The length is 7m.  (5m + 2m)
CHECKING our Answer***
  5m*7m = 35 m^2