Question 408282
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You have the right idea, but you misapplied the process of applying the common denominator.  You need to review the Distributive Property:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{c\ +\ 5}{7}\ +\ \frac{c\ -\ 3}{4}\ =\ \frac{5}{14}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4(c\ +\ 5)}{28}\ +\ \frac{7(c\ -\ 3)}{28}\ =\ \frac{2\,\cdot\,5}{28}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4c\ +\ 20}{28}\ +\ \frac{7c\ -\ 21}{28}\ =\ \frac{10}{28}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4c\ +\ 7c\ +\ 20\ -\ 21}{28}\ =\ \frac{10}{28}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{11c\ -\ 1}{28}\ =\ \frac{10}{28}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 11c\ =\ 11]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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