Question 408193
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Hi
mean of a normal probability distribution is 87 and the standard deviation is 4. 
*Note: {{{z = blue(x - mu)/blue(sigma)}}}
  z = (90-87)/4 = 3/4 = .75  |NORMSDIST(0.75) = .77337
 P(z > .75) = 1 - .77337 = .25335