Question 5432
2x-4y>-6 needs to be re-written into the form y=mx+c, so


2x+6>4y... or re-written, 4y<2x+6
--> y<x/2 + 3/2


So, the straight line has a gradient of 1/2 and passes through the y-axis at 3/2.


The question wants to know where y is less than x/2+3/2. By intuition, the line tells you the points where y EQUALS x/2+3/2, and so (hopefully, you can see that all the space below the line is where y is less than the line...so this is the region you require.


Jon.