Question 407895
If we have to let x=0 correspond to 1982 then the x for 1999 is found as 
x = 1999-1983
x = 16
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so
y = 100*16 + 2300
y = 1600 + 2300
y = 3900



{{{ graph( 3000, 3000, -30, 300, 2000, 4100, 100*x+2300, 3900) }}}