Question 407657
The Line equation is y-y1 = m*(x-x1) where m is the slope of the line.
As line is perpendicular to a line with slope m if its slope is 1/m.
So for a point (x,y) on the line m = (y-y1)/(x-x1).
if x = 4 for a line then m = (y-y1)/(4-4) = infinity.
the perpendicular has a slope of 1/infinity or 0.
so the equation of the line in question is
                     y-6 = 0*(x-3)
                     y-6 = 0
                     y = 6