Question 407537
The decrease in sec of race speed reduction of t years is, 
f(t) = (46.3-46.1)*(t/10)
f(t) = 0.2*(t/10)
f(t) = 0.2*t/10
f(t) = 0.2*t/10
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so for 2003
f(2003-1930) = 0.2*((2003-1930)/10))
f(t) = 1.46 secs will be the decrease, so the record speed is 
46.3 - 1.46 = 44.84
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To find the year when the record will be 44.50
             46.3 - f(t-1930) = 44.50
              -f(t-1930) = 44.50 - 46.3
              -f(t-1930) = -1.8
              f(t-1939) = 1.8
              0.2*(t-1930)/10 = 1.8 
              0.2*t = 18 + 0.2*1930
                   t = (18 + 386)/0.2
                   t = 2020