Question 43767
x^2/16 - y^2/4 = 1
Transverse Axis: horizontal
Center: (0,0)
a = 4
b = 2
c^2 = a^2 + b^2
c = sqrt(16 + 4)
c = sqrt(20) = 2*sqrt(5)
Vertices: (-4,0) and (4,0)
Foci: (-2*sqrt(5),0) and (2*sqrt(5),0)
{{{ graph( 600, 600, -10, 10, -10, 10, -sqrt(x^2/4 - 4), sqrt(x^2/4 - 4) ) }}}