Question 407513
{{{1/(7-5i)=(1/(7-5i))((7+5i)/(7+5i))=(1(7+5i))/((7-5i)(7+5i))=(7+5i)/(49-25i^2)=(7+5i)/(49-25(-1))=(7+5i)/(49+25)=(7+5i)/74=7/74+expr(5/74)i}}}



So {{{1/(7-5i)=7/74+expr(5/74)i}}}



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