Question 407381


{{{y=x^2+1}}} and 

{{{x+2y=5}}}...solve for {{{y}}}.......{{{x+2y=5}}}..=>..{{{2y=-x+5}}}
..=>..{{{y= -(1/2)x+2.5}}}

{{{ graph( 500, 500, -10, 10, -10, 10,-(1/2)x+2.5, x^2+1) }}}