Question 407409
  <pre><font size = 3 color = "indigo"><b>
Hi
graphing 
y = 2x^2 + 2
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 Vertex ix Pt(0,2) Line of symmetry is the y-axis.  parabola opens upward (a>0)
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(0, 2,0.3),
graph( 300, 300, -6, 6, -6, 6,2x^2+2))}}}