Question 406969
Let z = r-s



So we go from 7(r-s)+t(r-s) to 7z+tz



Now factor out a 'z' to get z(7+t)


Finally, plug in z=r-s to get (r-s)(7+t)



So 7(r-s)+t(r-s) factors to (r-s)(7+t)



In other words, 7(r-s)+t(r-s) = (r-s)(7+t)



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