Question 407338
{{{(1/36)x^2 - 4 x + 144 }}}
Use formula: {{{a^2-2*a*b+b^2=(a-b)^2}}}
{{{(1/36)x^2 - 4 x + 144 =((1/6)x)^2-2*(1/6)x*12+(12)^2=((1/6)x-12)^2}}}