Question 407009
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Hi
2x^2-5x-3=0   |Note use of ^(uppercase 6)
factoring
(2x +1)(x-3)= 0 Note:SUM of the inner product(1*x) and the outer product(-6x) = -5x
(2x +1)=0    x = -1/2
  (x-3)= 0   x = 3