Question 406929
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Hi
*[tex \large\ Using \ the \ standard \ slope-intercept \ form \ for \ an \ equation \ of \ a  \ line \ y = mx + b ] 
*[tex \LARGE\ where \ m \ is \ the \ slope \ and \ b \ the \ y-intercept]
 y = (-1/5)x + 2  |m = (-1/5)  Line &#8869; to it:  m = 5  (the negative reciprocal)
New Line
 y = 5x + b  |using ordered pair Pt(10,7) to solve for b
7 = 5*10 + b
-43 = b
 y = 5x - 43