Question 407300


{{{f(x)=(x+3)^2+1}}}

{{{f(x)=(x^2 +6x +9)+1}}}


{{{f(x)=x^2 +6x +10}}}

use quadratic formula 

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ...you have {{{a=1}}}, {{{b=6}}} and {{{c=10}}}


{{{x = (-6 +- sqrt( 6^2-4*1*10 ))/(2*1) }}}



{{{x = (-6 +- sqrt( 36-40 ))/2 }}}


{{{x = (-6 +- sqrt( -4 ))/2 }}}

{{{x = (-6 +- sqrt( 4i ))/2 }}}


{{{x = (-6 +- ( 2i ))/2 }}}


{{{x1 = (-6 +( 2i ))/2 }}}

{{{x1 = (-3 +( i ))}}}

{{{x1 = (-3 -( i ))}}}

graph:

{{{ graph( 500, 500, -10, 10, -20, 20, x^2 +6x +10) }}}