Question 406783
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Hi
three consecutive integers
Let x,(x+1),(x+2) represent the three consecutive integers
Question states***
x^2 +(x+1)^2+(x+2)^2 = 110
Solving for x
 3x^2 + 6x  + 5 = 110
 3x^2 + 6x  -105 = 0
 3(x^2 + 2x - 35)  = 0
  (x^2 + 2x - 35)  = 0 
factoring
  (x+7)(x-5) = 0 Note:SUM of the inner product(7x) and the outer product(-5x) = 2x
  (x+7)=0  |x = -7  The three consecutive integers are -5,-6,-7
  (x-5)=0  |x = 5   The three consecutive integers are 5,6,7


CHECKING our Answer(s)***
25 + 36 + 49 = 110