Question 407231
The mean weight of loads of brick is 46.0 tons with a standard deviation of 8 tons. 25 loads are chosen at random for a weight check. Find the probability that the mean weight of those loads is less than 44.24 tons. Assume that the variable is normally distributed.
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t(44.24) = (44.24-46)/[8/sqrt(25)] = -1.1
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P(x < 44.24) = P(t< -1.1 when df = 24) = 0.1411
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Cheers,
Stan H.
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