<PRE><B>Question 406733</B>
Trains A and B are traveling in the same direction on parallel tracks.
 Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h.
 Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m.
 At this rate, what time will Train B catch up to Train A?
:
from the given information, we know that train B is 30 min (1/2 hr) behind
 train A, when train A passes the station at 2:25PM
:
The distance between the trains at this time: {{{1/2}}} * 50 = 25 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 25 mi
50t = 40t + 25 
50t - 40t = 25
10t = 25
t = {{{25/10}}}
t = 2.5 hr or 2 hr 30 min
:
2:25 PM + 2:30 = 4:55 pm, B catches A
:
:
Check this by finding the travel distance of each train:
Train B: 50*2.5 = 125 mi
Train A: 40*2.5 = 100 mi
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dif in distance: 25 mi</PRE>