Question 406561
{{{df/dx = 2cos(2x)ln(x^2) + sin(2x)*((2x)/x^2) = 2cos(2x)ln(x^2) + sin(2x)*(2/x)

= 2cos2*ln1 + 2sin2 = 2sin2}}}

Hence the equation of the tangent line is y = 2sin2(x-1)